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5*5^2x=55
We move all terms to the left:
5*5^2x-(55)=0
Wy multiply elements
25x^2-55=0
a = 25; b = 0; c = -55;
Δ = b2-4ac
Δ = 02-4·25·(-55)
Δ = 5500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5500}=\sqrt{100*55}=\sqrt{100}*\sqrt{55}=10\sqrt{55}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{55}}{2*25}=\frac{0-10\sqrt{55}}{50} =-\frac{10\sqrt{55}}{50} =-\frac{\sqrt{55}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{55}}{2*25}=\frac{0+10\sqrt{55}}{50} =\frac{10\sqrt{55}}{50} =\frac{\sqrt{55}}{5} $
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